Brushless max amps
- Thread starter Andymicke
- Start date
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Think of it this way, the motor will "ask" for power from the Esc then the Esc will ask the battery to supply this level of requested power. If the motor is rated for 70a max and the Esc can handle at least 70a the Esc will be fine, the real worry is the battery may be able to supply WAY more that 70a so the Esc will push more amps to the motor and will overload it. This is a balancing act here, the motor/Esc/battery all work together but in the end the Esc is the weakest link most times.
L
lohring
Guest
Current, not voltage is what limits most components in an electric power plant. Power is volts times amps. It's always better to run a higher voltage for more power. Motors can be run for a while at well above their rated current. High current causes heating in the motor's wires, breaking down the insulation. Eventually this will cause a short. I don't know how your motor was rated, but it was probably with air cooling. Water cooling postpones this overheating to higher current levels.
As an example, the UL-1 motors are routinely operated at more than their rated current while water cooled. There's a point where their life is shortened, though. The stock UL-1 ESC will also fail at higher currents, but NAMBA allows a higher capacity ESC making the motor the weak link. We're racing so all components can be pushed beyond their ratings if a short life is acceptable.
Lohring Miller
As an example, the UL-1 motors are routinely operated at more than their rated current while water cooled. There's a point where their life is shortened, though. The stock UL-1 ESC will also fail at higher currents, but NAMBA allows a higher capacity ESC making the motor the weak link. We're racing so all components can be pushed beyond their ratings if a short life is acceptable.
Lohring Miller
Christian Lucas
Well-Known Member
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- Aug 23, 2012
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- 339
Hi,
thanks Lohring answer allways in mind " better to run at higher voltage for moore power" . I will give a short example how this will destroy conectors and cable and all part that have resistance in the electric circuite . The math for powerlos is powerlos in watt = resistance x ampdraw^2 . So if ampdraw rise from 2 amp to 4 amp the powerlos rise four times as resistanc of conector and all other part are stady set . Better to ad one moore cell than to rise propellerdia to get higher power . That is mostly the reason of burned esc and motors . Ok ,i know for class racing the number of cell are given and higher volts are not allowed ,so the only way seems to run higher ampsdraw but as the batterie has also a limited capasity you have only a max ampdraw to run full racing time . So very important is to run the motor at it's highest efficancy point to have the highest power at the propshaft.
thanks Lohring answer allways in mind " better to run at higher voltage for moore power" . I will give a short example how this will destroy conectors and cable and all part that have resistance in the electric circuite . The math for powerlos is powerlos in watt = resistance x ampdraw^2 . So if ampdraw rise from 2 amp to 4 amp the powerlos rise four times as resistanc of conector and all other part are stady set . Better to ad one moore cell than to rise propellerdia to get higher power . That is mostly the reason of burned esc and motors . Ok ,i know for class racing the number of cell are given and higher volts are not allowed ,so the only way seems to run higher ampsdraw but as the batterie has also a limited capasity you have only a max ampdraw to run full racing time . So very important is to run the motor at it's highest efficancy point to have the highest power at the propshaft.
